Physics, asked by ananjitkh12, 11 months ago

12.A bullet of mass 20 g has an initial speed of 1 ms,
just before it starts penetrating a mud wall of thickness 20
cm. If the wall offers a mean resistance of 2.5 * 10-N,
the speed of the bullet after emerging from the other side
of the wall is close to :
(a) 0.3 ms? (b) 0.1 ms-' (c) 0.7 ms? (d) 0.4 ms -1​

Answers

Answered by sonuvuce
10

Answer:

Option (c) 0.7 m/s

Explanation:

Mass of the bullet = 20 g

Initial speed of the bullet = 1 m/s

The bullet hits the wall with speed 1 m/s

After that a resisting force of 2.5 × 10⁻² N acts on the bullet

Acceleration due to this force = F/m = (2.5 × 10⁻²)/(20 × 10⁻³)

                                                            = 25/20

                                                            = 5/4 m/s²

Thickness of wall = 20 cm = 0.2 m

The bullet travels 0.2 m with a retardation of 5/4 m/s² acting on it

Using the third equation of motion

v² = u² - 2as

v² = 1² - 2 × (5/4) × 0.2

⇒ v² = 1 - 5 × 0.1

⇒ v² = 1 - 1/2 = 1/2

⇒ v = 1/√2 = √2/2 = 1.414/2 = 0.7 m/s

Therefore, the correct option is option (c)

Answered by singhrishiv06
0

Answer:

0.7 m/s

Explanation-

Mass of the bullet = 20 g

Initial speed of the bullet = 1 m/s

The bullet hits the wall with speed 1 m/s

After that a resisting force of 2.5 × 10⁻² N acts on the bullet

Acceleration due to this force = F/m = (2.5 × 10⁻²)/(20 × 10⁻³)

                                                           = 25/20

                                                           = 5/4 m/s²

Thickness of wall = 20 cm = 0.2 m

The bullet travels 0.2 m with a retardation of 5/4 m/s² acting on it

Using the third equation of motion

v² = u² - 2as

v² = 1² - 2 × (5/4) × 0.2

⇒ v² = 1 - 5 × 0.1

⇒ v² = 1 - 1/2 = 1/2

⇒ v = 1/√2 = √2/2 = 1.414/2 = 0.7 m/s

Therefore, the correct option is option (c)

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