12. A bullet of mass 50. g moving with an initial
velocity of 100 m s-1 strikes a wooden block
and comes to rest after penetrating a distance
2 cm in it. Calculate : (i) initial momentum of
the bullet, (ii) final momentum of the bullet,
(iii) retardation caused by the wooden block, and
(iv) resistive force exerted by the wooden block
Ans.(i) 5 kg m s-, (ii) zero,
(iii) 2.5 x 10 m s?, (iv) 12500 N
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Explanation:
Mass of the bullet is m
b
=50gm=0.05Kg
Initial velocity of bullet u
b
=100m/s
Final velocity is v
b
=0m/s
(1) Initial momentum of bullet p
i
=m
b
u
b
=5Kgm/s
(2) Final momentum of bullet p
f
=m
b
v
b
=0.05×0=0
(3) Retardation occurred by the wooden block is
v
2
−u
2
=2as
−(100)
2
=2a(0.02)
a=−250000m/s
2
(4) Resistive force
F=ma
=0.05×−250000
=12500N
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