Question

12. A car hire firm has 2 cars which is hired out everyday. The number of demands per dayfor a car follows Poisson distribution with mean 1.20. What is the proportion of days onwhich some demand is refused? (Given e 1.20 = 3.32).(a) 0.25(b) 0.3012(c) 0.12(d) 0.03​

Answer 1

Step-by-step explanation:

Given A car hire firm has 2 cars which is hired out everyday. The number of demands per day for a car follows Poisson distribution with mean 1.20. What is the proportion of days on which some demand is refused?

• We have P(x) = λ^x x e^-λ / x!
• Now demand (mean) will be λ = 1.2
• So if demand is 0,1,2 then demand is not refused and if it is more than 2 then demand is refused.
• Now demand not refused will be P(0) + P(1) + P(2)
•                                                  = 1.2 ^0 x e^- 1.2 / 0! + 1.2^1
•                                                = 0.301 + 0.361 + 0.216
•                                                  = 0.878
• Now demand refused will be 1 – 0.878
•                                              = 0.122

Therefore proportion of days on which some demand is refused will be 0.12

Reference link will be

https://brainly.in/question/19982036