12. A car is moving with initial velocity 36km/hr and moving with uniform accelera-
tion 2 m/s. Then distance travelled in 3sec is
1) 29m
2) 39m
3) 21m
4) 22m
with explanation
Answers
Answered by
0
Answer:
initial velocity (u)= 36km/hr
=36×5/18
=10m/s
acceleration=2m/s
time(t)= 3s
first, find Velocity=
v=u+at
v=10+2×3
v=10+6=16
2as=v²–u²
2×2×s=(16)²–(10)²
4s=256–100
4s=156
s=156/4s=39 m
Similar questions