Question

12. A car is moving with initial velocity 36km/hr and moving with uniform accelera-
tion 2 m/s. Then distance travelled in 3sec is
1) 29m
2) 39m
3) 21m
4) 22m
with explanation​

Answer 1

Answer:

initial velocity (u)= 36km/hr

=36×5/18

=10m/s

acceleration=2m/s

time(t)= 3s

first, find Velocity=

v=u+at

v=10+2×3

v=10+6=16

2as=v²–u²

2×2×s=(16)²–(10)²

4s=256–100

4s=156

s=156/4s=39 m