Question

12. A circular piece of thin wire is converted into a rhombus of side 11 cm. Find
diameter of the circular piece.
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Answer 1

Perimeter of Rhombus = 11 × 4 = 44 cm

Circumference of circle = 44 cm

2πr = 44 cm

$2 \times \frac{22}{7} \times r = 44cm$

r = 7 cm.

d = 2r

= 2 × 7 cm

= 14 cm.

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Answer 2

Answer:

14

Step-by-step explanation:

Perimeter of rhombus=11×4=44

so the circumference of circular piece of thin wire=44cm

so 2πr=44

r=7

diameter=7×2=14