Question

12: A continuous beam ABC is fixed at A and simply
supported at B and C. Length of spans AB=4m, BC=
4m. The beam is carrying a uniformly distributed load
of 2 kNm over the span AB and a point load of 8 KN is
applied at the mid span of BC. Determine the support
reaction at C.​

Answer 1

Answer:

A fixed beam AB of length 6m carries point load of 160 kN and 120 kN at a distance of 2m and 4m from the left end A. Find the fixed end moments and the reactions at the supports. Draw B.M and S.F diagrams.

Answer 2

Answer: 16 KN upwards

Explanation:

• Given:- Length of AB is 4 and is carrying a uniformly distributed load of 2 KN/m. Also, a point load of 8KN is applied at the middle of BC.
• To Find:- Support reaction at C.
• Solution:-
• Total load of AB= (4*2) KN

                                   = 8 KN downwards

• Load of BC= 8 KN downwards.
• So, load to support C= (8 + 8) KN

                                           = 16 KN upwards

• Hence, the required support reaction at C is 16 KN upwards.

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