Question

12. A converging lens forms a real and inverted image of an object at a distance of 100cm from it. Where should an object
be placed in front of the lens, so that the size of the image is twice the size of the object? Also, calculate the power of a
lens
what dem hich is placed 15cm from a convex lens of focal length 5 cm. Draw a ray diagram and find the​

Answer 1

here os your answer

the lens is converging,it is convex

image dist. v=100

m=2

-v/u=2

u=-100/2

u=-50

according to lens formula,

1/f=1/v - 1/u

1/f=1/100 - 1/-50

1/f=1/100 = + 1/50

1/f =(1+2)/100

1/f = 3/100

f=100/3

f=33.33

hence,

power,p=1/f(in m)

p=1/33.33 × 10^-2

p=3D

hope this helps:-)