Question

12. A diagonal of a quadrilateral is 40 m long and theperpendiculars to it from the opposite corners
are 8 m and 10 m respectively. Find its area.​

Answer 1

Let the diagonal = d= 4o m

perpendiculars to the diagonal are h1, h2

h1 = 8m

h2 =10m

area of the quadrilateral = (h1+h2)d/2

= (8+10)*40/2

=18*20

=360sq m

thanks