Question

12. A fish with a mass of 3 kg causes a fishing pole to bend 9 cm. If the amount of bending varies direct
as the mass, how much will the pole bend for a 2 kg fish?​

Answer 1

mass = 3 kg

bend = 9 cm

mass = 2 kg

bend = x

Let us take it in proportional form.

DIRECT VARIATION ( given )

X1 : X2 :: Y1 : Y2

3 : 2 :: 9 : x

Product of means = product of extremes

3 × x = 2 × 9

3x = 18

x = 18/3

x = 6

therefore, the rod will bend 6 cm if the weight of the fish is 2 kg

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Answer 2

Answer:

6 cm

Step-by-step explanation:

here we have the variation proportion which is as follows:

∴ mass of fish(m) ∝ length of bending of pole (l)

∴ m ∝ l

Now removing the proportion sign we introduce constant K.

∴ m = K*l

∴ K = $\frac{m}{l}$

now putting $m_{1}$ = 3 kg and $l_{1}$ = 9 cm and $m_{2}$ = 2 kg and $l_{2}$ = ?

∴ $\frac{m_{1} }{l_{1} }$ = $\frac{m_{2} }{l_{2} }$

∴ $l_{2}$ = $\frac{m_{2} *l_{1}}{m_{1} }$

∴ $l_{2}$ = $\frac{2*9}{3}$

∴ $l_{2}$ = 6 cm

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