Question

12. A force of 50 kgf is applied to the smaller piston of
hydraulic machine. Neglecting friction, find the force
exerted on the large piston, if the diameters of the
pistons are 5 cm and 25 cm respectively.

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plsss answer​

Answer 1

Answer:

the force applied on large piston will be 1250 kgf

Explanation:

if on 5 cm

ratio = 25:625

then solving

50/kgf =25/625

kgf. = 1250

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