Question

12. A garrison of 120 men has provision for 30 days. At the end of five days,five more men joined . How many days can they sustain on the remaining provision ?​

Answer 1

120=30

30-5=120+5

25=125

125/25

5

Answer 2

Answer:

Answer

We know that no. of days is inversely propotional to the provision for men.

So for 120 men the provision would last for 30days. (given)

Therefore, the provision for 1 men would sustain for. 120 *30 = 3600 days.

Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days

A.t.q 120*30 = 120*5+125*x

(120*30) - (120*5)= 125x

120(30-5)=125x

120 * 25 = 125x

120 = 5x

x=120/5

x= 24

so the provision would remain for more 24 days.