Question

12. A ladder 41 m long reaches on a wall of a building 9 m above the ground. Determine the distance of the foot of the ladder from the building.​

Answer 1

Step-by-step explanation:

let AB be the height of the building= 9m

let AC be the ladder= 41 m

by applying pythagoras theorem in the traingle ABC

${ac}^{2} = {ab}^{2} + {bc}^{2}$

${41}^{2} = {9}^{2} + {bc}^{2}$

on solving this

we get BC= 40 mtrs approx