Question

12. A lift is moving up with an acceleration equal to g÷5. the
apparent weight of 60 kg man standing in the lift is
A) 48 kg b) 72 kg c) 60 kg d) 12 kg

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Answer 1

Given

mass of the person = 60 kg

acceleration of lift (a) = g/5 , where g is acceleration due to gravity ( g = 10m/s²)

The apparent weight of a person when lift is moving up = m(g+a)

Apparent weight = m(g+a)

Apparent weight = 60 [ 10 + (10/5) ]

Apparent weight = 60 [ 10 +2 ]

Apparent weight = 60 × 12 = 720 N = 72 kgf

OPTION (B) is correct