Question

12. A lorry moving with uniform acceleration covers
a distance of 180 m from point A to point B along
a straight path in 15 s. Its velocity , while passing
through point B, is 20 m s-1.
(a) What is the velocity of the lorry at the time of
passing through point A?
(b) What is its acceleration?

please , I need the solution asap, with full process.​

Answer 1

Answer:

The velocity of the lorry at the time of passing through point A is 4 m/s and acceleration of the lorry is  

Explanation:

Given the distance covered by the lorry, AB (d) = 180 m.

Time taken from point A to B, t = 15 s.

The initial velocity at A = u = ?

The final velocity  of lorry at point B, v = 20 m/s.

Formula for distance covered by a particle moving in a  straight line with uniform acceleration is given as,

substitute the given values, we get

24m/s = u + 20 m/s

u = 4 m/s.

Now to calculate the acceleration of the lorry, use first equation of motion as,

v = u + at

20 m/s = 4 m/s + a x 15 s

Thus, the velocity of the lorry at the time of passing through point A is 4 m/s and acceleration of the lorry is .