Question

12. A man throws ball into the air one after the other
Throwing one when other is at the highest point.
How high the balls rise if he throws twice a
second.​

Answer 1

Answer:

A man throws ball into the air one after the other

Throwing one when other is at the highest point.

How high the balls rise if he throws twice a

second.​

Which means after 0.5 second, the ball reaches its maximum height.

Now,

h=?

u=v+gt (v=u-gt)

u=0+10*0.5

u=5 m/s

v=0 m/s

Putting these in the equation v^2 - u^2=-2gh

0–5^2 = -2×10×h

h=1.25 m.