Question

12.
A particle is projected from ground at an
angle 45° with initial velocity 20/2 ms.
The magnitude of average velocity in a
time interval from t = 0 to t = 3 s in ms-'is
1) 20.62 2) 10.31 3) 41.14 415.15​

Answer 1

Answer:

x direction mein velocity constant rhegi mtlb change 0 hoga...

y dirn m phle thi 20 root(2) × sin 45

= 20m/s

after 3 seconds

y mein velocity.. v = U-gt se aayegi.. jo hogi -10m/s

avg vel = change / time

= -10-20/3 =-10

...if the ans comes out to be wrong just del thw ans....