Math, asked by encounterali790, 6 months ago

12. A piece of wire is bent in the shape of an equilateral triangle each of whose sides measures
8.8 cm. This wire is rebent to form a circular ring. What is the diameter of the ring?​

Answers

Answered by asahilthakur
5

Answer:

8.4 cm

Step-by-step explanation:

Side of triangle = 8.8 cm

Perimeter of triangle = 3×8.8 cm = 26.4 cm

Hence, the length of wire is 26.4 cm.

Circumference of circle = πd

=> 22/7 × d = 26.4

=> d = 26.4 × 7/22

=> d = 8.4 cm

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