Question

12. A rectangle measures 60cm in length and 40cm in its breadth, find the ratio of length and breadth. ​

Answer 1

In context to questions asked,

We have to determine the ratio of length and breadth of the rectangle.

As per questions,

It is given that

Length of rectangle = 60 cm

Breadth of rectangle = 40 cm

So, dividing both for getting the ratio,

We will get,

$\frac{60}{40} = \frac{6}{4} = \frac{3}{2}$

Hence ratio between length and breadth of rectangle is 3:2

Answer 2

★ Concept

Here the concept of ratio (:) has been used. The term 'Ratio' signifies the process of comparison. In this question we have to find the ratio of length to breadth i.e how much times the length of the rectangle is greater than the breadth. We're given with the measures for both Length and Breadth and thus, by dividing length to breadth we can easily find its respective ratio.

Let's proceed with calculation !!

$\rule{190pt}{1pt}$

Elucidation

Given that, in a rectangle

» Length = 60 cm

» Breadth = 40 cm

Ratio of Length to Breadth = Length/Breadth = 60cm/40cm

[zero will be cancelled out along with units]

= 6/4 = 3/2 (simplest form)

Ratio of Length to Breadth = 3/2 or 3:2

∴ Required Ratio = 3:2

☞ Note

➠ 3/2 can also be written as 3:2 i.e a basic way to represent a ratio. It's read as 'three is to two'.

➠ Ratio is pure i.e it doesn't contain any unit even taken this question as an example we find that unit 'cm' has been cancelled.

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Illustrative Diagram

Below shows a rectangle with length 60cm and breadth 40cm such that they bears a ratio of 3:2 .

$\begin{gathered} \begin{gathered} \sf{ \red{40 \: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \sf\footnotesize{Req.\: Ratio = 3:2}\\ \: \: \: \end{array}} \\ \: \: \: \: \: \sf{ \red{60 \: c m}}\end{gathered} \end{gathered}$