Question

12. A rectangular field is 70 m x 60 m. A well of dimensions 14 mx 5 mx 6 m is dug outside the field
and the earth dug out from this well is evenly spread over the rectangular field. How much will
the earth level of the field rise?​

Answer 1

$\large \bf \: QUESTION$

A rectangular field is 70 m x 60 m. A well of dimensions 14 mx 5 mx 6 m is dug outside the field and the earth dug out from this well is evenly spread over the rectangular field. How much will the earth level of the field rise?

$\large \bf \: SOLUTION$

$Volume \: of \: well = 14 m \times 8 \times 6m \: \\ 672 {m}^{3}$

Volume of field = Volume of well

→ Length,Breath, Height = 672

$height \: = \frac{672}{length \times breath}$

$= > \: \frac{672}{60 \times 70}$

$0.16 \: m=16 \: cm .$

Hence, the earth level of the field rise is 16 cm

Verified☑

Answer 2

Answer:

$\\ \\ \huge\bigstar \bf \underline\color{lime}{ \underline{required \: answer}} \bigstar$

• Volume of well=14m×8×6m=672m³

• Volume of field = Volume of well

→ Length,Breath, Height = 672

$\large\bf height \: = \frac{672}{length \times breath}$

$\large\bf = > \: \frac{672}{60 \times 70}$

$\bf 0.16 \: m=16 \: cm$

• Hence, the earth level of the field rise is 16 cm