Question

12. A scooter was bought at ₹ 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.

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Answer 1

principal(p) = Rs.42,000

Rate of interest (R) = 8%

Time(n) = 1 years

Amount(A) = P(1-R/100)^n

42,000 = (1-8/100)^1

42,000 = (1+2/25)^1

42,000 = 27/25

= Rs,38,640

Therefore the valur of scooter after 1 year is Rs.38640

Answer 2

$\huge{\boxed{\mathfrak{Answer}}}$

Here, Principal (P) = Rs. 42,000, Rate of Interest (R) = 8%, Time (n) = 1 years

Amount (A) = P ( 1 - R/100)n

= 42000(1 - 8/100)1

= 42000(1+ 2/25)1

= 42000 (27/25)1

= 42000 × 27/25

= Rs. 38,640

Hence, the value of scooter after one year is Rs. 38,640.