Question

12. A scooter was bought at 7 42,000. Its value
depreciated at the rate of 8% per annum.
Find its value after one year.​

Answer 1

Step-by-step explanation:

Here, Principal (P) = Rs. 42,000, Rate of Interest (R) = 8%, Time (n) = 1 years.

Amount (A) = P\left(1-\frac{R}{100}\right)^nP(1−100R)n

= 42000\left(1-\frac{8}{100}\right)^142000(1−1008)1

= 42000\left(1+\frac{2}{25}\right)^142000(1+252)1

= 42000\left(\frac{27}{25}\right)^142000(2527)1

= 42000\times\frac{27}{25}42000×2527

= Rs. 38,640