Question

12. A ship sails 33 km due south and then 56 km due
west. How far is it from its starting point?​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

149

Answer 2

Answer:

Answer is 65 km as using Pythagoras theorem we can solve it

AC^2= AB^2 +BC^2

AC^2=(33^2)+(56^2)

AC^2=1089+3136

AC^2=4225

AC=√4225

AC =65 Km

therefore the distance from the starting point and the ending point is 65 Km

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