Question

12. A stone is dropped from a tower of height 490 m. If g=9.8 m/s2, time
taken by it to reach the ground is
O a) 10 S
O b) 5 S
O c)15 s
O d) 20 s
13. In above question, what is the velocity of the stone on reaching the​

Answer 1

Answer:

S= Ut +½at²

490=(0)t + ½(9.8)(t²)

980= 9.8(t²)

t=10sec

Answer 2

Answer:

a) 10 s

Explanation:

because this formula is work for this question

s = ut +1/2gt 2