Question

12. A stone is dropped on the surface of the moon from
on the moon is 1.67 m/s2. Determine the time for
the stone to fall to the surface of the moon.
[Ans. t=1.29 s]​

Answer 1

Answer is 1.29 s

Explanation:

Given, acceleration a=1.67m/s^2

Distance covered by feather d=1.40m

Distance covered by feather d=1.40m Initial velocity u=0m/s (assume heather falls from rest)

Distance covered by feather d=1.40m Initial velocity u=0m/s (assume heather falls from rest)Using formula

S=ut+1/2at^2

1.40=0(t)+ 1/2 (1.67)t^2

or t ^2 =2.8/1.67=1.68

=2.8/1.67=1.68 t = √(1.68)

=1.29s....

Please give the vote