Question

12. A stone of mass 2.0 kg is allowed to fall freely from the top of a cliff of height
60 m. What is the kinetic energy of the stone when it just reaches the ground?
(Given that g = 10 m/s²).​

Answer 1

Answer:

the velocity of stone to reach the ground is =v=√2gh

v²=2gh

v²=2×10×60

v²=1200-----------------(1)

kinetic energy(k.e)=1/2×mv²

k.e=1/2×2×1200

k.e= 1200 joules

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