12. A stone of mass 2.0 kg is allowed to fall freely from the top of a cliff of height60 m. What is the kinetic energy of the stone when it just reaches the ground?(Given that g = 10 m/s²).
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Explanation:
Solving for v^2
v^2 = 2 * g * h
v^2 = 2 * 9.8 n/s^2 * 60 m
V^2 = 1176 (m/s)^2
Solving for its kinetic energy
K.E. = 1/2 * m * v^2
K.E. = 1/2 * 2 kg * 1176 (m/s)^2
K.E. = 1176 joules
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