Question

12. A stone of mass 2.0 kg is allowed to fall
freely from the top of a cliff of height
60 m. What is the kinetic energy of the
stone when it just reaches the ground?
(Given that g = 10 m/s2)​

Answer 1

Answer:

KE = 1/2mv²

m = 2 kg h = 60m

v² = u² + 2gh since initial velocity is zero, u =0

v² = 2 × 10 × 60

v² = 1200

KE = 1/2 × 2 × 1200

KE = 1200 J

Step-by-step explanation:

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Answer 2

Answer:

dkhsyjjejgb j68/5-*554866%