12) A train is moving with a velocity 400 m/s. With the application of brakes a retardation of 10 m/s' is produced.
find the following:
(1) After how much time it will stop? (ii) How much distance will it travel before it stops?
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Given,
Initial Velocity (u) = 400 m/s
Final Velocity (v) = 0
Acceleration (a) = -10 m/s
Time taken to stop (t) = ?
Distance travelled before it stops (s) = ?
We know that ,
t = (v-u)÷a = (-400)÷(-10) = 40 seconds Ans.
Also ,
s = (v² - u²)÷2a = (0 - 160000)÷(-10)
=> s = 16000 metres = 16 kilometres Ans.
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