Question

12. A train leaves the city at 2 pm. A second train leaves the city at 4 pm and follows the first train. The
second train's speed is 32 km/h faster than the first train's speed. If the second train overtakes the
first train at 8 pm, find the speeds of both the trains.​

Answer 1

Answer:

Let

v = the speed of the first train

v + 162 = the speed of the second train

t1 = 10 - 2 = 8 hr the time of the first time

t2 = 10 - 8 = 2 ht the time of the second time

Since both trains travel the same distance we have:

vt1 = (v + 162)t2 (we use the formula distance = speed*time)

8v = 2(v + 162)

v = 54 mph

v + 162 = 54 + 162 = 216 mph

The speed of the first train is 54 mph while the speed of the second train is 216 mph.