Question

12. A train running with a speed of 18 m/s crosses a stationary man in 8 s. Find the length of
the train.

if you answer it I will mark you as brainliest ​

Answer 1

Answer:

Length of the first train=180m

Time taken by the train to cross the man standing on the platform=12s

Speed of the first train=

12

180

=15m/s

Speed of the second train=

3

2

×15

=10m/s

Relative speed=15+10

=25m/s

Let the length of the train be y metres.

Distance=Speed×time

y+180=25×12

y+180=300

y=300−180

y=120

So, the length of the second train=120m

Answer 2

Step-by-step explanation:

speed of train = 18 m/s

time taken to cross the man = 8 s

$speed \: = \frac{distance}{time}$

$distance \: = speed \: \times time$

= 18 × 8

= 144 m

PLEASE MARK BRAINLIEST...