12. A train travelling at a uniform speed passes a 455-m-long platform in 17 seconds and
another platform. 175 m long, in 10 seconds. Find the (i) length and (ii) speed of the train.
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Answer:
hi dear...
Step-by-step explanation:
Given s = t + 220/30 ------ (1)
and s = t + 325/39 ------ (2)
on solving (1) and (2), we get
39(t + 220) = 30(t + 325)
39t + 8580 = 30t + 9750
9t = 1170
t = 130 metres
Substitute in (1), we get
Speed = 130 + 220/30
= 350/30
= 11.66 m/sec
On converting it to km/hr, we get
S = 3600 * 11.66/1000
= 41.9
= ~42
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