Question

12.
A wire is in the shape of a square of perimeter 40 cm. It is rebent in the form of a
rectangle of width 8 cm. Find the area of rectangle. Compare whose area is more, the
square or the rectangle?​

Answer 1

Step-by-step explanation:

Hope this will help you!!

pls mark me as BRAINLIST

Answer 2

Question

A wire is in the shape of a square of perimeter 40 cm. It is rebent in the form of a  rectangle of width 8 cm. Find the area of rectangle. Compare whose area is more, the  square or the rectangle?​

$\rule{300}{1}$

Answer

Perimeter of Square ⇒ 4 × Side

Perimeter of Square ⇒ 40 cm

Length of 1 side ⇒ Perimeter ÷ 4

Length of 1 side ⇒ 40 ÷ 4 = 10 cm

Area of square ⇒ Side²

Area of square ⇒ 10² = 100 cm²

Perimeter of rectangle ⇒ 2 × (l + b)

Perimeter of rectangle ⇒ 40 cm

Length of breadth ⇒ 8 cm

Length of length ⇒ 2 × (l + 8)

⇒ $2l+16 = 40$

⇒ $2l=40-16$

⇒ $2l = 24$

⇒ $l = 24\div 2$

⇒ $l =12 \ cm$

Area of rectangle ⇒ Length × Breadth

Area of rectangle ⇒ 12 × 8 = 96 cm²

∴The area of square is more than the rectangle.

∴ 100 > 96

∴ The difference between the area of the square and rectangle is 100 - 96 = 4

$\rule{300}{1}$