Question

12. A wire of 32 resistance and 10 cm length is stretched to
30cm length. Assuming that it has uniform cross section,
what will be its new resistance?
send the solved format plzz
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Answer 1

Volume must be conserved.

A1L1=A2L2

10A1=A2×30

32=rho ×10/A1

R=rho × L/A

=rho ×30/A2

put the value of A2

you will get the answer.