Question

12. ABCD is a parallelogram. Mis the mid-point
of AB and Pis a point on diagonal BD such that
BP = 1 BD. MP produced meets BC at N.
4
Prove that:
(i) N is a mid-point of BC.
(i) MN = 1/2AC​

Answer 1

(1) join AC

Let the intersecting point is O

now OD=OB

BP=1/2 OB

in triangle AOB

M and P are mid point of BO

Mp||AO

so in triangle BOC Pi's mid point of BO and PN||OC

from converse of mid point theorem N is mid point of BC

(2)now in triangle ABC M and N are mid point hence MN=1/2AC

Answer 2

Answer:

This is your answer ..

Step-by-step explanation:

Thus , This may help you ☝️