Question

12. According to Bohr's atomic model, the circumference of the electron orbit is always
an
multiple of de Broglie wavelength.
​

Answer 1

Answer:

2πr=nλ I.e., an integral multiple of de Broglie wavelength

Explanation:

Bohr, in his atomic model, considered an electron to be in form of a standing electron wave and if this wave is to be continuous over the circumference of the stationary orbit that the electron lies in the circumference must be an integral multiple of its wavelength (nλ).