Question

12. Amit walks 16 m south from his house and turns east to walk 63 m to reach his
friend's house. While returning, he walks diagonally from his friend's house to reach
back to his house. What distance did he walk while returning?
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Answer 1

Answer:

In this diagram AB = 16m and BC= 63m

according to question,when he walks diagonally......then by PYTHAGORAS THEOREM

H²=P²+B²

H²= (16m)²+(63m)²

H² = 256m² +3969m²

H² = 4225m²

H = √4225m²

H= 65m

.°. AC= 65m

So he walks 65m diagonally

Answer 2

Answer:65

Step-by-step explanation:

Distance walk while returning is (63^2 + 16^2)^.5 = 65m