Question

12. An aeroplane left 50 minutes later than its scheduled time, and in order to reach the
destination, 1250 km away, in time, it had to increase its speed by 250 km/hr from its
usual speed. Find its usual speed.​

Answer 1

Usual speed = 500 km/hr

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Answer 2

let the usual speed of plane = x km/h

distance = 1250km

then, speed = distance/ time

time =

$time\: \: \: = \frac{1250}{x}$

Case 2nd

speed in this case = ( x + 250)km/h

$time = \frac{1250}{x + 250}$

now according to question

50min = 5/6hr

$\frac{1250}{x} - \frac{1250}{x + 250} = \frac{5}{6}$

on solving this u will get a quadratic equation

${x}^{2} + 250x - 375000$

on solving this quadratic equation u will get speed

${x}^{2} + 750x - 500x - 375000$

here u will get

x = - 750

x = 500

speed = 500 km/h

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