Chemistry, asked by gpslookhi, 4 days ago

12. An air compressor used with a paint sprayer does 67.0 J of work pumping air into a tank. Warmed by the process, the air in the tank gives off 33.0 J of energy to its surroundings. What is the change in the internal energy of the air in the tank as a result of the two processes?

Answers

Answered by pathuribhavishya
0

Answer:

According to the First Law of Thermodynamics based on the law of conservation of energy, the change in the internal energy (ΔU)(ΔU) of a system is equal to the energy (Q)(Q) supplied to the system plus the work (W)(W) on the system by the surrounding and is expressed as:

ΔU=Q+W

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