12 )An element "X" with atomic number 3 and mass number 7. How many neutrons are present in element "X"?
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O 3
O4
O5
O7
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Answer:
Explanation:
no of neutrons = mass no-atomic no
no of neutrons=7-3
no of neutrons=4
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Atomic no = no of neutrons +protons=7
Now no of protons= no of electrons = atomic no (for neutral atom)=3
Therefore no of neutrons =7-3=4
Now no of protons= no of electrons = atomic no (for neutral atom)=3
Therefore no of neutrons =7-3=4
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