Question

12. An integer is chosen at random between 1 and
100. Find the probability that it is:
(i) divisible by 8.
(ii) not divisible by 8.please answer to my question​

Answer 1

Step-by-step explanation:

¡ 12÷100 = 0.12

¡¡ 88÷100 = 0.88

Answer 2

Sample space (S) = {2, 3, 4 ...98, 99}

n(S) = 98

(i) An integer is divisible by 8 E = {8, 16, 24, 32 ... 96}

n(E) = 12

$\sf[ n= \frac{96 - 8}{8} + 1 ]$

Probability of chosen a number divisible by 8

P(E) = n(E)/n(S)

= 12/98

= 6/49

Probability of chosen a number divisible by 8

= 6/49

(ii) Probability of chosen a number is not divisible by 8 = P (bar E)

$\sf \: p(E) = 1 - p(E)$

$\sf = 1 - \frac{6}{49} = \frac{49 - 6}{49}$

$\sf \: p(E) = \frac{43}{49}$

Probability of chosen a number is not divisible by 8 = 43/49.