Question

12. An object of height 2.0 cm is placed perpendicular
to the principal axis of a concave lens of focal
length 12 cm. Find the height of the image, if the
object is placed at a distance of 8.0 cm from the
lens.​

Answer 1

Answer:

Explanation:

height of object, h = 2cm

focal length of concave lens, f = -12cm object distance from the lens, u = -8cm using lens maker formula,

1/v - 1/u = 1/f

or, 1/v1/-8 = 1/-12

or, 1/v = 1/-12 + 1/-8

or, 1/v = -(8 +12)/96

or, 1/v = -20/96

or, v = -4.8cm

hence, image distance from lens, v = -4.8cm

now magnification for lens, m = v/u

or, height of image/height of object = v/u

or, height of image/2cm = (-4.8cm)/(-8cm)

or, height of image = 1.2cm

hence, image is virtual, diminished. and height of image is 1.2cm

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