Question

12. An ore contains 15% iron. How much ore will be required to get 18 kg of iron?
​

Answer 1

$\begin{gathered} \\ \Large{\bf{\green{\underline{AnSwEr\::}}}} \\ \end{gathered}$

Amount of iron contains 18 kg of ore = 2.7 kg

$\begin{gathered} \\ \Large{\bf{\red{\underline{GiVeN\::}}}} \\ \end{gathered}$

• Percentage of iron that ore contains = 15 %

$\begin{gathered} \\ \Large{\bf{\purple{\underline{To \: FiNd\::}}}} \\ \end{gathered}$

• Amount of ore contains for 18 kg.

$\begin{gathered} \\ \Large{\bf{\pink{\underline{SoLuTiOn\::}}}} \\ \end{gathered}$

Percentage of iron that ore contains = 15 %

Then,

Amount of iron contains 18kg of ore=$\sf \: 18 \times \frac{15}{100} kg$

⇒2.7 kg

Amount of iron contains in 18kg of ore = 2.7kg

Answer 2

An ore contains 15% iron. How much ore will be required to get 18 kg of iron?

(100×18)÷15 = 120 kg