12. At what distance on the axis, from the centre of circular current carrying coil of 16. TI th 1 radius R, the magnetic field becomes of the magnetic field at 27 centre? (2) 2R 17 (1) VER (3) 2V2R (4) 2/3R
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Answer:
B
axis
=
2(r
2
+x
2
)
3/2
μ
0
Ir
2
B
center
=
2r
μ
0
I
B
axis
=
8
1
B
center
(r
2
+x
2
)
3/2
r
2
=
8r
1
(2r)
2
=r
2
−x
2
x=r
3
Explanation:
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