Question

12.
aths-3110_Practical
Construct a quadrilateral ABCD given that
CD = 7 cm, AD = 5 cm, angle A = 90°, angle B = 105°
and angle C = 135°​

Answer 1

The quadrilateral ABCD as shown in figure.

Step-by-step explanation:

Given that,

$\angle A = 90^{o},\, \angle B = 105^{o}, \, \angle C = 135^{o}$

We know that the sum all interior angle of quadrilateral is .

$\angle A + \angle B +\angle C+\angle D = 360 ^{o}\\\\90^{o}+105^{o}+135^{o} + \angle D =360 ^{o}\\\\\angle D = 30^{o}$

Procedure

Consider line CD = 7 cm as the base line.

At vertex C and D draw angle  and   respectively.

Cut an arc from the vertex D at A = 5 cm.

At vertex A draw an angle $90^{o}$

Extend the vertex C until it does not cot line AB.  

The quadrilateral ABCD as shown in figure.

Answer 2

Answer:

Here, in this case quadrilateral cant be constructed.