Question

12 bags of rice contain the following waiting rice kg 4.937, 5.005, 5.08, 5.03, 5.00, 5.06, 5.08, 5.07, 5.04, 4.98, 5.00, 4.98, find the probability that any one of these bags chosen at random contains more than 5 kg of rice

Answer 1

P(E) = Number of trials / Total number of trials
=7/12
=0.583...

Answer 2

total no. of outcomes=12
bags containing more than 5kg of rice= favourable outcomes= 7
probability of getting a bag more than 5kg of rice = 7/12

hope this helps:p