Question

12. Balance the following equation by ion electron method in basic medium.
MnO4^-1 (aq) + Br^-1 (aq) –
+ MnO2 (s) + BrO3^-1 (aq)

plz explain in brief also​

Answer 1

Hi there,

Oxidation number of oxygen is -2 lets calculate the other elements

MnO4^-1 => Mn = +7

Br^-1 => Br = -1

MnO2 => Mn = +4

BrO3^-1 = > Br = +5

So, Mn reduced and Br oxidized

Lets balance each half reaction

• MnO4 = MnO2

• MnO4 = MnO2 + 2H2O

☆ 3e+ 4H2O + MnO4 = MnO2 + 2H2O + 4OH

The other half

• Br = BrO3

• 3H2O + Br = BrO3

• 3H2O + Br = BrO3 + 6H2O

The sum of two halfs

☆ 6OH + Br = BrO3 + 3H2O + 6e

☆ 6e + 4H2O + 2MnO4 = 2MnO2 + 8OH

The equation

◇ Br^-1 + H2O + 2MnO4^-1 = 2OH^-1 + BrO3^- + 2MnO2

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