Question

12 bit a/d converter the range of input signal is 0 to 10 volt. The voltage corresponds to 1 lsb is

Answer 1

ADC has a resolution of one part in 4,096, where 212 = 4,096. Thus, a 12-bit ADC with a maximum input of 10 VDC can resolve the measurement into 10 VDC/4096 = 0.00244 VDC = 2.44 mV. Similarly, for the same 0 to 10 VDC range, a 16-bit ADC resolution is 10/216 = 10/65,536 = 0.153 mV.

Answer 2

Answer:

The voltage corresponds to 1 lsb is 2.44mV.

Explanation:

Given a 12 bit Analog to Digital converter, i.e., N=12

The range of input signal is from 0 to 10 Volt, i.e., $V_{ref}=10V$

• LSB, least significant bit, is the smallest level that an Analog to Digital converter(ADC) can convert.
• Analog to Digital converter(ADC) converts an analog signal to the digital signal.
• The voltage corresponding to LSB is the resolution of ADC, that is the voltage required to change to the digital output by 1 LSB.
• Depending on the bits that an ADC has, ADC divides the voltage to small levels called counts, given by $2^{N}$.

Given ADC is a 12 bit ADC.

Therefore, $2^{N}=2^{12}=4096$

ADC has a resolution of one part in 4,096.

Thus, a 12-bit ADC with a maximum input of 10 V can resolve the measurement into 1LSB, given by

$1LSB=\dfrac{V_{ref} }{2^{N} }$

          $=\dfrac{10 }{4096 } =0.00244V$

          $=0.00244V=2.44mV$

Therefore, the voltage corresponds to 1 LSB is 2.44mV.