Question

12 boys and 2 girls are to be seated in a row such that are at least 3 boys between the two girls.Then the number of wats it can be done is

Answer 1

Step-by-step explanation:

arrangement in two girls are together = 2 x 13 = 26

=> one boy sit between two girls = 2 x 12 = 24

=> two boys sit between two girls = 2 x 11 = 22

=> Total arrangements = 14!

∴ required arrangements 14! - (26 + 24 + 22)12! = 110 . 12! = 11P2 12!