Question

12 boys can do a work in 8 days. How many boys are required to same work in 6 days

Answer 1

The number of boys required to do the same work in 6 days is 16.

Given,

12 boys can do a particular work in 8 days.

To find,

The number of boys required for the same work in 6 days.

Solution,

Firstly, the relationship between the number of men and the time required to finish a work is given by

$M_1D_1 =M_2D_2 \hfill ...(1)$

where,

$M_1$ men can finish a particular work in $D_1$ days, and

$M_2$ men can finish the same work in $D_2$ days.

Here, it is given that,

12 boys take 8 days to do a particular work.

Let the number of boys to finish the same work in 6 days be N.

Thus, on substituting the respective values in (1), we get,

12 × 8 = N × 6

Rearranging and simplifying,

$N=\frac{12 \times 8}{6} =\frac{96}{6}$

⇒ N = 16.

So, the number of boys = 16.

Therefore, the number of boys required to do the same work in 6 days is 16.

#SPJ2

Answer 2

Answer:

The boys required are $16$.

Step-by-step explanation:

It is given that twelve boys can do a work in eight days.

We need to determine that how many boys are required to so same work in six days.

We know that the relationship between the number of men and the time required to finish a work is given by:

$M_{1} D_{1} =M_{2} D_{2}$

Here,

$M_{1} =12$

$D_{1} =8$

$M_{2}=?$

$D_{2} =6$

Using it, we get

$12*8=M_{2}*6$

$M_{2}=96/6=16$

We require sixteen boys.

#SPJ2