Math, asked by tanmay7171, 7 months ago

12. By how much does 8x³ – 6x² + 9x – 10 exceed 4x³ + 2x² + 7x - 3?​

Answers

Answered by Anonymous
4

Step-by-step explanation:

8x³ – 6x² + 9x – 10 - (4x³ + 2x² + 7x - 3)

4x³-8x²-2x-13 Ans.

Answered by Parneetkaursandhu
6

Step-by-step explanation:

Subtract both terms

8x^3-6x^2+9x-10-(4x^3+2x^2+7x-3)

8x^3-6x^2+9x-10-4x^3-2x^2-7x+3

8x^3-4x^3-6x^2-2x^2+9x-7x-10+3

4x^3-8x^3+2x-7

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